Samm. 13 Posted October 30, 2009 okay it says... let "a" be the number of digits of 2^2001., and let "b" be the number of digits 5^2001. Compute the sum of digits "a+b" (Hint: 2^5=32 which is 2 digits and 5^5=3125 which is 4 digits, therefore, the sum of the digits is 6)ANSWER AND HOW? Quote Share this post Link to post Share on other sites
Howard Dean 2502 Posted October 30, 2009 Why dont you go on webcam with organikk, for every answer you get correct he can strip or you can just strip for him and stuff! Quote Share this post Link to post Share on other sites
dankfrank 0 Posted October 30, 2009 wheres hairy when you need him Quote Share this post Link to post Share on other sites
Samm. 13 Posted October 30, 2009 Why dont you go on webcam with organikk, for every answer you get correct he can strip or you can just strip for him and stuff!Hold on, I'll just call you.wheres hairy when you need himHe's in the middle of a game. Quote Share this post Link to post Share on other sites
Howard Dean 2502 Posted October 30, 2009 Just call me on skype without any clothes on plox... Quote Share this post Link to post Share on other sites
fontaine 1744 Posted October 30, 2009 http://www.wolframalpha.com Quote Share this post Link to post Share on other sites
Samm. 13 Posted October 30, 2009 I TOLD YOU NO! It has to be done as if using only a piece of paper and a pencil. ajkdlfa;sdfadks Quote Share this post Link to post Share on other sites
Serial 3 Posted October 30, 2009 the answer is 475 485 023 495 NO SOUP FOR YOU! 8585 44894898458958 FIND ANSWER IN BRAIN! HOMEWORK IS FOR MOMMY TO DO NOT INTERWEB GAMERZ! Quote Share this post Link to post Share on other sites
Howard Dean 2502 Posted October 30, 2009 Serial, wanna chat on the webcam? im not wearing any clothes! Quote Share this post Link to post Share on other sites
Serial 3 Posted October 30, 2009 Serial, wanna chat on the webcam? im not wearing any clothes!im sorry i have standards Quote Share this post Link to post Share on other sites
Empire 30 Posted October 30, 2009 ....... How the hell are you supposed to solve that unless you keep it in algebraic form and don't actually find the numbers. I mean you could say the sum of the numbers is 3a b/c you have twice the number of digits in the 5^2001 to the 2^2001, but I have no clue otherwise.Eh... just finished my Calc3 hwk so my brains a little fried, but maybe i'll be able to help later.edit:alright i think i got it:it takes 2^4 to get a new digit after 128 (2^7)it takes 5^2 to get a new digit after 125 (5^3)so 2001 - 7 = 1994/4 = something = a2001 - 5 = 1996/2 = something = b add 3 to each and you should be setthis is a pretty much random brainstorm that i did in 5 mins Quote Share this post Link to post Share on other sites
Howard Dean 2502 Posted October 30, 2009 Empire is obviously Asian, just saying... Quote Share this post Link to post Share on other sites
Serial 3 Posted October 30, 2009 empire you better have skype cuz your about to get a big surprise Quote Share this post Link to post Share on other sites
Audiovox 6 Posted October 30, 2009 See below.-Audio Quote Share this post Link to post Share on other sites
Howard Dean 2502 Posted October 30, 2009 Lol that problem would have taken me an hour to do and i still would have gotten it wrong, fuck math, im so happy that my brain is right sided and not left sided, because then i would just fail at life... Quote Share this post Link to post Share on other sites
Empire 30 Posted October 30, 2009 lol audiovox wins... Quote Share this post Link to post Share on other sites
Audiovox 6 Posted October 30, 2009 Actually, I might be off by one, lemme recheck it and possibly add another way of explaining it. I'll edit this post with more info.-AudioEDIT: Okay, the calculations I provided earlier still count, but I disregarded a small bit of info. The method for finding the number of digits in any given number is take the log base 10 of the number and round that down, then add one. The method I provided is basically what I said there, but I'll show both ways below. I rounded the wrong way when I did the first calculation lol so here's the correct way to view it, and I'll edit the above post to reflect this change:2001 * log(2) = 602.36102132363so602 + 1 = 603 or the number of digits in 2^20012001 * log(5) = 1,398.63897867637so 1398 + 1 = 1399 or the number of digits in 5^2001603 + 1399 = 2002, not 2001 like I suggested earlier, my bad for rounding the 2nd number the wrong way lolOkay, so here's the way I defined above:log(2^2001)/log(10) = 602.36102132....rounded down that is 602, like above, add 1 and you get 603. aka the number of digits in 2^2001log(5^2001)/log(10) = 1398.638978....rounded down that is 1398 blah blah blah so we still get 2002 when all said and done.SO, the answer is 2002, not 2001, I rounded incorrectly on the 2nd number above. If you're going to turn this in, I suggest you use the base ten method, as that is more precise supposedly, but either work for this case. Quote Share this post Link to post Share on other sites
Serial 3 Posted October 30, 2009 i dont see a reason why your in school anyway because of this "292. Women belong in the kitchen. No exceptions. Unless it is in the bedroom." So I guess the only valid question is Why aren't you in the kitchen? WHORE. Quote Share this post Link to post Share on other sites
Contract Killer 24 Posted October 30, 2009 Hold on, I'll just call you. He's in the middle of a game.I love you howard, but you just got fucking owned. Quote Share this post Link to post Share on other sites
Serial 3 Posted October 30, 2009 SAVE THE SEA KITTENS! Quote Share this post Link to post Share on other sites
B'laz.e 10 Posted October 30, 2009 SAVE THE SEA KITTENS!Still posting like a tard eh? Quote Share this post Link to post Share on other sites
Ben 161 Posted October 30, 2009 okay it says... let "a" be the number of digits of 2^2001., and let "b" be the number of digits 5^2001. Compute the sum of digits "a+b" (Hint: 2^5=32 which is 2 digits and 5^5=3125 which is 4 digits, therefore, the sum of the digits is 6)ANSWER AND HOW?I liek your coconutsalso, that math is hard. Quote Share this post Link to post Share on other sites
Serial 3 Posted October 30, 2009 Still posting like a tard eh?you know it Quote Share this post Link to post Share on other sites
GodzillA 0 Posted October 31, 2009 Doing it without a calculator can be done like thislogs are base 10c1=log(2^2001)c2=log(5^2001)Rules of logsc1=2001log(2)c2=2001log(5)Algebrac1+c2=2001log(2)+2001log(5)Rules of logsc1+c2=2001log(2*5)c1+c2=2001log(10)Rules of logsc1+c2=log(10^2001)Algebra10^2001 has 2002 digits, shown by 10^1 having 2 digits, 10^2 has 3 digits etc etc. Quote Share this post Link to post Share on other sites
